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Problems/Problem 8 (1985 AJHSME)

Problem 8 (1985 AJHSME)

AJHSMEVery Easy

From module Algebra Basics

Problem

If $a = -2$ , the largest number in the set $\{-3a, 4a, \frac{24}{a}, a^2, 1\}$ is

Select an answer

$-3a$
$4a$
$\frac{24}{a}$
$a^2$
$1$

Show me the solution

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