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Problems/Problem 4 (1991 AJHSME)

Problem 4 (1991 AJHSME)

AJHSMEVery Easy

From module Algebra Basics

Problem

If $991+993+995+997+999=5000-N$ then $N=$

Select an answer

$5$
$10$
$15$
$20$
$25$

Show me the solution

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