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Problem 2 (1994 AJHSME)

AJHSMEVery Easy

From module Arithmetic and Number Theory Basics

Problem

110+210+310+410+510+610+710+810+910+5510=\frac{1}{10}+\frac{2}{10}+\frac{3}{10}+\frac{4}{10}+\frac{5}{10}+\frac{6}{10}+\frac{7}{10}+\frac{8}{10}+\frac{9}{10}+\frac{55}{10}=

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