Overview

Complex numbers extend the real line to a plane. Most AMC/AIME problems start with algebraic manipulation and then switch to geometry when convenient.

Algebra with complex numbers is the same as real algebra, except you keep i2=1i^2 = -1 and collect real and imaginary parts.

Conjugates turn complex expressions into real numbers and are essential for solving equations and simplifying fractions.

Key Ideas

  • z=a+biz = a + bi with i2=1i^2 = -1.
  • Powers of ii repeat every 44.
  • Real part is aa, imaginary part is bb.
  • (a+bi)±(c+di)=(a±c)+(b±d)i(a+bi) \pm (c+di) = (a\pm c) + (b\pm d)i.
  • (a+bi)(c+di)=(acbd)+(ad+bc)i(a+bi)(c+di) = (ac-bd) + (ad+bc)i.
  • Solve equations by isolating zz and rationalizing with conjugates.
  • If z=a+biz = a+bi, then z=abi\overline{z} = a-bi.
  • zz=a2+b2=z2z\overline{z} = a^2 + b^2 = |z|^2.
  • Use conjugates to rationalize denominators.

Core Skills

Separate Real and Imaginary Parts

Write z=a+biz=a+bi and equate real and imaginary parts to solve equations.

Use i2=1i^2=-1 Early

Simplify powers of ii before multiplying out to avoid sign mistakes. Especially when using FOIL.

Convert Between Forms

Switch between algebraic and geometric interpretations when helpful.

Solve Linear Equations

Isolate zz and use conjugates to rationalize denominators.

Equate Parts

If z=wz=w, then real and imaginary parts must match separately.

Rationalize Denominators

Multiply by the conjugate to remove ii from denominators.

Convert to Real Equations

Use z+z=2(z)z+\overline{z}=2\Re(z) and zz=z2z\overline{z}=|z|^2 to switch to real variables.

Use Modulus Identities

If z|z| is fixed, relate aa and bb via a2+b2a^2+b^2.

Worked Examples

Example 1

Compute i2023i^{2023}.

Powers of ii cycle with period 44. Since 20233(mod4)2023 \equiv 3 \pmod 4, i2023=i3=ii^{2023} = i^3 = -i.

Example 2

If z+6i=izz + 6i = iz, find zz.

Rearrange: ziz=6iz - iz = -6i, so z(1i)=6iz(1-i) = -6i. Then z=6i1i=6i(1+i)(1i)(1+i)=66i2=33iz = \frac{-6i}{1-i} = \frac{-6i(1+i)}{(1-i)(1+i)} = \frac{6-6i}{2} = 3-3i.

Example 3

Let z+z=6z + \overline{z} = 6 and zz=13z\overline{z} = 13. Find zz.

Write z=a+biz = a+bi. Then 2a=62a=6 so a=3a=3. Also a2+b2=13a^2+b^2=13 so b2=4b^2=4 and b=±2b=\pm 2. Thus z=3±2iz = 3 \pm 2i.

More Examples

Example 1: Add and Multiply

Compute (3+2i)(14i)(3+2i)(1-4i).

312i+2i8i2=1110i3-12i+2i-8i^2 = 11-10i.

Example 2: Solve a Simple Equation

Solve z+2i=34iz+2i=3-4i.

z=36iz=3-6i.

Example 3: Powers of ii

Compute i58i^{58}.

582(mod4)58\equiv 2\pmod 4, so i58=1i^{58}=-1.

Example 4: Multiply

Compute (1+2i)(35i)(1+2i)(3-5i).

35i+6i10i2=13+i3-5i+6i-10i^2 = 13+i.

Example 5: Solve for zz

Solve (2i)z=5+7i(2-i)z = 5+7i.

z=5+7i2i=(5+7i)(2+i)5=3+19i5z = \frac{5+7i}{2-i} = \frac{(5+7i)(2+i)}{5} = \frac{3+19i}{5}.

Example 6: Match Real/Imag

If (a+bi)(1i)=4+2i(a+bi)(1-i)=4+2i, find aa and bb.

Expand: (a+b)+(ba)i=4+2i(a+b) + (b-a)i = 4+2i, so a+b=4a+b=4 and ba=2b-a=2. Thus a=1a=1, b=3b=3.

Example 7: Rationalize

Simplify 3+2i14i\frac{3+2i}{1-4i}.

Multiply by 1+4i1+4i: (3+2i)(1+4i)1+16=5+14i17\frac{(3+2i)(1+4i)}{1+16} = \frac{ -5+14i}{17}.

Example 8: Modulus

If z=5|z|=5 and (z)=3\Re(z)=3, find (z)\Im(z).

a2+b2=25a^2+b^2=25 gives b=±4b=\pm 4.

Example 9: Real Product

If z=23iz=2-3i, compute zzz\overline{z}.

Strategy Checklist

  • Reduce powers of ii modulo 44.
  • Keep real and imaginary parts separate and equate real and imaginary parts when solving equations.
  • Check arithmetic with i2=1i^2=-1. Especially when using FOIL.
  • Rationalize denominators, use the conjugate to eliminate ii in denominators.
  • Replace zz with a+bia+bi to solve real equations.
  • Use z2|z|^2 to relate real and imaginary parts.

Common Pitfalls

  • Forgetting the period 44 for powers of ii.
  • Treating the imaginary part as bibi instead of bb.
  • Dropping the i2=1i^2=-1 sign change.
  • Forgetting to rationalize the denominator.
  • Mixing real and imaginary parts after expansion.
  • Mixing up z+zz+\overline{z} with 2z2|z|.
  • Forgetting that z\overline{z} changes the sign of the imaginary part only.
  • Dropping the denominator after multiplying by the conjugate.

Practice Problems

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