Overview

The Law of Sines is an important tool for solving non-right triangles. It connects side lengths and opposite angles in a clean ratio and is especially effective when at least one side-angle opposite pair is known.

For a triangle ABC\triangle ABC with side lengths a,b,ca,b,c opposite A,B,CA,B,C respectively, the law states:

asinA=bsinB=csinC=2R\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=2R

where RR is the circumradius.

This topic appears often in olympiad geometry and trigonometric geometry because it lets you switch between angle information and length information quickly.

Key Ideas

  • Opposite pairs matter: aAa \leftrightarrow A, bBb \leftrightarrow B, cCc \leftrightarrow C.
  • The law is strongest when you know an angle and its opposite side.
  • The circumradius form a=2RsinAa=2R\sin A is often the fastest path.
  • Combine with A+B+C=180A+B+C=180^\circ to generate missing angles first.
  • In SSA data (two sides and a non-included angle), check for the ambiguous case (0, 1, or 2 triangles).

Statement and Equivalent Forms

The standard ratio form is:

asinA=bsinB=csinC.\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}.

Equivalent pairwise forms are:

ab=sinAsinB,bc=sinBsinC,ca=sinCsinA.\frac{a}{b}=\frac{\sin A}{\sin B},\qquad \frac{b}{c}=\frac{\sin B}{\sin C},\qquad \frac{c}{a}=\frac{\sin C}{\sin A}.

With circumradius RR:

a=2RsinA,b=2RsinB,c=2RsinC.a=2R\sin A,\quad b=2R\sin B,\quad c=2R\sin C.

These forms are algebraically equivalent; choose the one that isolates the unknown most directly.

Why It Is True (Quick Derivation)

Use area formulas from different bases. Let KK be the area of ABC\triangle ABC.

K=12bcsinA=12casinB=12absinC.K=\frac12 bc\sin A=\frac12 ca\sin B=\frac12 ab\sin C.

From 12bcsinA=12casinB\frac12 bc\sin A=\frac12 ca\sin B, cancel common factors:

sinAa=sinBb.\frac{\sin A}{a}=\frac{\sin B}{b}.

Similarly,

sinBb=sinCc.\frac{\sin B}{b}=\frac{\sin C}{c}.

So all are equal, giving the Law of Sines.

To get asinA=2R\frac{a}{\sin A}=2R, use the extended chord relation in a circle: a side of the triangle is a chord of the circumcircle.

When to Use Law of Sines vs. Law of Cosines

Use Law of Sines when:

  • You know AAS/ASA data (two angles and a side).
  • You know SSA data and want to test possible triangles.
  • You need circumradius or expressions involving 2R2R.

Use Law of Cosines when:

  • You know SSS (all three sides).
  • You know SAS and need the third side.
  • You need an equation with cos\cos of an included angle.

Core Skills

Match Each Side to Its Opposite Angle

Label the triangle so that aa is opposite AA, and so on, before writing the ratio. This avoids the most common mistake.

Use the Circumradius Form

If RR is known or requested, use a=2RsinAa=2R\sin A directly.

Solve for the Unknown with One Ratio

Do not use the full chain unless needed. Set up one proportion containing only one unknown and solve cleanly.

Use Angle Sum Early

If one angle is missing, compute it first using

A+B+C=180.A+B+C=180^\circ.

Then apply Law of Sines with a known opposite pair.

Ambiguous Case (SSA)

Suppose you know AA, aa, and bb, where AA is not included between known sides. From

asinA=bsinB\frac{a}{\sin A}=\frac{b}{\sin B}

you get

sinB=bsinAa\sin B=\frac{b\sin A}{a}

Now check possibilities:

  • If bsinAa>1\frac{b\sin A}{a}\gt 1, no triangle exists.
  • If bsinAa=1\frac{b\sin A}{a}=1, exactly one right-triangle case for BB.
  • If 0<bsinAa<10\lt\frac{b\sin A}{a}\lt 1, then potentially two angles: B1=arcsin ⁣(bsinAa)B_1=\arcsin\!\left(\frac{b\sin A}{a}\right) and B2=180B1B_2=180^\circ-B_1.

Keep only values where A+B<180A+B\lt 180^\circ.

Worked Example

In ABC\triangle ABC, A=30A=30^\circ, B=45B=45^\circ, and a=10a=10. Find bb.

10sin30=bsin45101/2=b2/2.\frac{10}{\sin 30^\circ}=\frac{b}{\sin 45^\circ} \quad\Rightarrow\quad \frac{10}{1/2}=\frac{b}{\sqrt2/2}.

So

20=2b2=b2b=202=102.20=\frac{2b}{\sqrt2}=b\sqrt2 \quad\Rightarrow\quad b=\frac{20}{\sqrt2}=10\sqrt2.

More Examples

Example 1: Find an Angle

In ABC\triangle ABC, a=8a=8, b=10b=10, and A=30A=30^\circ. Find BB.

8sin30=10sinBsinB=10sin308=58.\frac{8}{\sin 30^\circ}=\frac{10}{\sin B} \quad\Rightarrow\quad \sin B=\frac{10\sin30^\circ}{8}=\frac{5}{8}.

Thus

B1=arcsin(58),B2=180B1.B_1=\arcsin\left(\frac58\right), \qquad B_2=180^\circ-B_1.

Both may be valid depending on the remaining data. This is the SSA ambiguous case in action.

Example 2: Circumradius

If a=12a=12 and A=45A=45^\circ, find RR.

12=2Rsin45=2R22=R212=2R\sin45^\circ=2R\cdot\frac{\sqrt2}{2}=R\sqrt2

so

R=122=62.R=\frac{12}{\sqrt2}=6\sqrt2.

Example 3: Find a Side After Angle Sum

Given A=50A=50^\circ, C=60C=60^\circ, and c=14c=14, find aa.

First,

B=1805060=70.B=180^\circ-50^\circ-60^\circ=70^\circ.

Then apply Law of Sines with known pair (c,C)(c,C):

asin50=14sin60a=14sin50sin60.\frac{a}{\sin50^\circ}=\frac{14}{\sin60^\circ} \quad\Rightarrow\quad a=14\cdot\frac{\sin50^\circ}{\sin60^\circ}.

Strategy Checklist

  • Label opposite sides and angles clearly before substituting.
  • Use the triangle angle sum to compute a missing angle first.
  • Keep unit of angle measurement consistent (degrees vs radians).
  • Check whether Law of Cosines is a better fit for SSS/SAS.
  • In SSA, explicitly test for 0/1/2 possible triangles.

Common Pitfalls

  • Using degrees for some angles and radians for others.
  • Swapping which side corresponds to which angle.
  • Forgetting to test both θ\theta and 180θ180^\circ-\theta in SSA.
  • Rounding too early and losing accuracy in later steps.

Summary

Law of Sines is a conversion tool between side lengths and opposite angles. Its most useful forms are

asinA=bsinB=csinC=2R\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=2R

and

a=2RsinA.a=2R\sin A.

Use it by matching opposite pairs carefully, computing missing angles early, and checking the SSA case whenever applicable.

Practice Problems

StatusSourceProblem NameDifficultyTags
AIME IMedium
Show TagsAngle Bisector, Geometry, Law of Sines, Triangle
AMC 12AHard
Show TagsGeometry, Law of Cosines, Law of Sines, Triangle
AIME IHard
Show TagsGeometry, Incenter, Law of Sines, Triangle

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